8/3=(6k-28)/(2k-6)

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Solution for 8/3=(6k-28)/(2k-6) equation: 



8/3=(6k-28)/(2k-6)

We move all terms to the left:

8/3-((6k-28)/(2k-6))=0



Domain of the equation: (2k-6))!=0

k∈R



We calculate fractions


(-((6k-28)*3)/6k+16k/6k=0

We can not solve this equation

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