5(6+4b)+2b=96

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Solution for 5(6+4b)+2b=96 equation: 



5(6+4b)+2b=96

We move all terms to the left:

5(6+4b)+2b-(96)=0

We add all the numbers together, and all the variables

5(4b+6)+2b-96=0

We add all the numbers together, and all the variables

2b+5(4b+6)-96=0

We multiply parentheses

2b+20b+30-96=0

We add all the numbers together, and all the variables

22b-66=0

We move all terms containing b to the left, all other terms to the right

22b=66

b=66/22

b=3

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