8/2x+21/7X=3

Solution for 8/2x+21/7X=3 equation:

8/2x+21/7x=3

We move all terms to the left:

8/2x+21/7x-(3)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: 7x!=0

x!=0/7

x!=0

x∈R


We calculate fractions


56x/14x^2+42x/14x^2-3=0

We multiply all the terms by the denominator


56x+42x-3*14x^2=0

We add all the numbers together, and all the variables

98x-3*14x^2=0

Wy multiply elements

-42x^2+98x=0

a = -42; b = 98; c = 0;
Δ = b2-4ac
Δ = 982-4·(-42)·0
Δ = 9604
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9604}=98$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(98)-98}{2*-42}=\frac{-196}{-84}
=2+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(98)+98}{2*-42}=\frac{0}{-84}
=0
$