5-3x-(2x+2)(x+1)=0

Solution for 5-3x-(2x+2)(x+1)=0 equation:

5-3x-(2x+2)(x+1)=0

We multiply parentheses ..

-(+2x^2+2x+2x+2)-3x+5=0

We get rid of parentheses

-2x^2-2x-2x-3x-2+5=0

We add all the numbers together, and all the variables

-2x^2-7x+3=0

a = -2; b = -7; c = +3;
Δ = b2-4ac
Δ = -72-4·(-2)·3
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{73}}{2*-2}=\frac{7-\sqrt{73}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{73}}{2*-2}=\frac{7+\sqrt{73}}{-4}
$