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(2x+4)(2x-4)=x
We move all terms to the left:
(2x+4)(2x-4)-(x)=0
We add all the numbers together, and all the variables
-1x+(2x+4)(2x-4)=0
We use the square of the difference formula
4x^2-1x-16=0
a = 4; b = -1; c = -16;
Δ = b2-4ac
Δ = -12-4·4·(-16)
Δ = 257
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{257}}{2*4}=\frac{1-\sqrt{257}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{257}}{2*4}=\frac{1+\sqrt{257}}{8} $
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