8/10(12+x)=7/10(20+x)

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Solution for 8/10(12+x)=7/10(20+x) equation: 



8/10(12+x)=7/10(20+x)

We move all terms to the left:

8/10(12+x)-(7/10(20+x))=0



Domain of the equation: 10(12+x)!=0

x∈R





Domain of the equation: 10(20+x))!=0

x∈R



We add all the numbers together, and all the variables

8/10(x+12)-(7/10(x+20))=0

We calculate fractions


(80xx/(10(x+12)*10(x+20)))+(-70xx/(10(x+12)*10(x+20)))=0



We calculate terms in parentheses: +(80xx/(10(x+12)*10(x+20))), so:

80xx/(10(x+12)*10(x+20))

We multiply all the terms by the denominator


80xx

Back to the equation:

+(80xx)





We calculate terms in parentheses: +(-70xx/(10(x+12)*10(x+20))), so:

-70xx/(10(x+12)*10(x+20))

We multiply all the terms by the denominator


-70xx

Back to the equation:

+(-70xx)



We get rid of parentheses

80xx-70xx=0

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