((5x+2)/3)+2-((2x-3)/4)=1/2

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Solution for ((5x+2)/3)+2-((2x-3)/4)=1/2 equation: 



((5x+2)/3)+2-((2x-3)/4)=1/2

We move all terms to the left:

((5x+2)/3)+2-((2x-3)/4)-(1/2)=0

We add all the numbers together, and all the variables

((5x+2)/3)-((2x-3)/4)+2-(+1/2)=0

We get rid of parentheses

((5x+2)/3)-((2x-3)/4)+2-1/2=0

We calculate fractions


(((5x+2)*4)*2)/()+(-((2x-3)*3)*2)/()+2+()/()=0



We calculate terms in parentheses: +(((5x+2)*4)*2)/(), so:

((5x+2)*4)*2)/(

We multiply all the terms by the denominator


((5x+2)*4)*2)



We calculate terms in parentheses: +((5x+2)*4)*2), so:

(5x+2)*4)*2

We multiply parentheses

10x+

We add all the numbers together, and all the variables

10x

Back to the equation:

+(10x)



Back to the equation:

+(10x)





We calculate terms in parentheses: +(-((2x-3)*3)*2)/(), so:

-((2x-3)*3)*2)/(

We multiply all the terms by the denominator


-((2x-3)*3)*2)



We calculate terms in parentheses: -((2x-3)*3)*2), so:

(2x-3)*3)*2

We multiply parentheses

4x+

We add all the numbers together, and all the variables

4x

Back to the equation:

-(4x)



Back to the equation:

+(-4x)



We add all the numbers together, and all the variables

10x+(-4x)+3=0

We get rid of parentheses

10x-4x+3=0

We add all the numbers together, and all the variables

6x+3=0

We move all terms containing x to the left, all other terms to the right

6x=-3

x=-3/6

x=-1/2

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