8/(2x+12)=6/(x+8)

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Solution for 8/(2x+12)=6/(x+8) equation: 



8/(2x+12)=6/(x+8)

We move all terms to the left:

8/(2x+12)-(6/(x+8))=0



Domain of the equation: (2x+12)!=0

We move all terms containing x to the left, all other terms to the right

2x!=-12

x!=-12/2

x!=-6

x∈R





Domain of the equation: (x+8))!=0

x∈R



We calculate fractions


8x/((2x+12)*(x+8)))+(-(6*(2x+12))/((2x+12)*(x+8)))=0



We calculate terms in parentheses: -(6*(2x+12))/((2x+12)*(x+8))), so:

6*(2x+12))/((2x+12)*(x+8))

We multiply all the terms by the denominator


6*(2x+12))

We multiply parentheses

12x+

We add all the numbers together, and all the variables

12x

Back to the equation:

-(12x)



We add all the numbers together, and all the variables

-12x+8x/((2x+12)*(x+8)))+(=0

We multiply all the terms by the denominator


-12x*((2x+12)*(x+8)))+(+8x=0

We add all the numbers together, and all the variables

8x-12x*((2x+12)*(x+8)))+(=0

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