8-x2=-9+7x

Solution for 8-x2=-9+7x equation:

8-x2=-9+7x

We move all terms to the left:

8-x2-(-9+7x)=0

We add all the numbers together, and all the variables

-x2-(7x-9)+8=0

We add all the numbers together, and all the variables

-1x^2-(7x-9)+8=0

We get rid of parentheses

-1x^2-7x+9+8=0

We add all the numbers together, and all the variables

-1x^2-7x+17=0

a = -1; b = -7; c = +17;
Δ = b2-4ac
Δ = -72-4·(-1)·17
Δ = 117
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{117}=\sqrt{9*13}=\sqrt{9}*\sqrt{13}=3\sqrt{13}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-3\sqrt{13}}{2*-1}=\frac{7-3\sqrt{13}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+3\sqrt{13}}{2*-1}=\frac{7+3\sqrt{13}}{-2}
$