2(t-1)=4(1-t)-1+t

Solution for 2(t-1)=4(1-t)-1+t equation:

2(t-1)=4(1-t)-1+t

We move all terms to the left:

2(t-1)-(4(1-t)-1+t)=0

We add all the numbers together, and all the variables

2(t-1)-(4(-1t+1)-1+t)=0

We multiply parentheses

2t-(4(-1t+1)-1+t)-2=0


We calculate terms in parentheses: -(4(-1t+1)-1+t), so:

4(-1t+1)-1+t

determiningTheFunctionDomain
4(-1t+1)+t-1

We add all the numbers together, and all the variables

t+4(-1t+1)-1

We multiply parentheses

t-4t+4-1

We add all the numbers together, and all the variables

-3t+3

Back to the equation:

-(-3t+3)


We get rid of parentheses

2t+3t-3-2=0

We add all the numbers together, and all the variables

5t-5=0

We move all terms containing t to the left, all other terms to the right

5t=5

t=5/5

t=1