8-7/10c=6-1/5c

Solution for 8-7/10c=6-1/5c equation:

8-7/10c=6-1/5c

We move all terms to the left:

8-7/10c-(6-1/5c)=0


Domain of the equation: 10c!=0

c!=0/10

c!=0

c∈R



Domain of the equation: 5c)!=0

c!=0/1

c!=0

c∈R


We add all the numbers together, and all the variables

-7/10c-(-1/5c+6)+8=0

We get rid of parentheses

-7/10c+1/5c-6+8=0

We calculate fractions


(-35c)/50c^2+10c/50c^2-6+8=0

We add all the numbers together, and all the variables

(-35c)/50c^2+10c/50c^2+2=0

We multiply all the terms by the denominator


(-35c)+10c+2*50c^2=0

We add all the numbers together, and all the variables

10c+(-35c)+2*50c^2=0

Wy multiply elements

100c^2+10c+(-35c)=0

We get rid of parentheses

100c^2+10c-35c=0

We add all the numbers together, and all the variables

100c^2-25c=0

a = 100; b = -25; c = 0;
Δ = b2-4ac
Δ = -252-4·100·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-25}{2*100}=\frac{0}{200}
=0
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+25}{2*100}=\frac{50}{200}
=1/4
$