8+7/10c=6+1/5c

Solution for 8+7/10c=6+1/5c equation:

8+7/10c=6+1/5c

We move all terms to the left:

8+7/10c-(6+1/5c)=0


Domain of the equation: 10c!=0

c!=0/10

c!=0

c∈R



Domain of the equation: 5c)!=0

c!=0/1

c!=0

c∈R


We add all the numbers together, and all the variables

7/10c-(1/5c+6)+8=0

We get rid of parentheses

7/10c-1/5c-6+8=0

We calculate fractions


35c/50c^2+(-10c)/50c^2-6+8=0

We add all the numbers together, and all the variables

35c/50c^2+(-10c)/50c^2+2=0

We multiply all the terms by the denominator


35c+(-10c)+2*50c^2=0

Wy multiply elements

100c^2+35c+(-10c)=0

We get rid of parentheses

100c^2+35c-10c=0

We add all the numbers together, and all the variables

100c^2+25c=0

a = 100; b = 25; c = 0;
Δ = b2-4ac
Δ = 252-4·100·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-25}{2*100}=\frac{-50}{200}
=-1/4
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+25}{2*100}=\frac{0}{200}
=0
$