8-5(r+2)=6(1-r)

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Solution for 8-5(r+2)=6(1-r) equation: 



8-5(r+2)=6(1-r)

We move all terms to the left:

8-5(r+2)-(6(1-r))=0

We add all the numbers together, and all the variables

-5(r+2)-(6(-1r+1))+8=0

We multiply parentheses

-5r-(6(-1r+1))-10+8=0



We calculate terms in parentheses: -(6(-1r+1)), so:

6(-1r+1)

We multiply parentheses

-6r+6

Back to the equation:

-(-6r+6)



We add all the numbers together, and all the variables

-5r-(-6r+6)-2=0

We get rid of parentheses

-5r+6r-6-2=0

We add all the numbers together, and all the variables

r-8=0

We move all terms containing r to the left, all other terms to the right

r=8

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