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8-4/3-2(5x+8)=2(4x+6)/9+2(10x+1)
We move all terms to the left:
8-4/3-2(5x+8)-(2(4x+6)/9+2(10x+1))=0
Domain of the equation: 9+2(10x+1))!=0We multiply parentheses
We move all terms containing x to the left, all other terms to the right
2(10x+1))!=-9
x∈R
-10x-(2(4x+6)/9+2(10x+1))-16+8-4/3=0
We calculate fractions
-10x+(-(2(4x+6)*3)/(2(10x+1))*3+9)+(2(10x+1))-4*9)/(2(10x+1))*3+9)-16+8=0
We calculate terms in parentheses: +(-(2(4x+6)*3)/(2(10x+1))*3+9), so:
-(2(4x+6)*3)/(2(10x+1))*3+9
We multiply all the terms by the denominator
-(2(4x+6)*3)+9*(2(10x+1))*3
We calculate terms in parentheses: -(2(4x+6)*3), so:We get rid of parentheses
2(4x+6)*3
We multiply parentheses
24x+36
Back to the equation:
-(24x+36)
-24x+9*(2(10x+1))*3-36
Back to the equation:
+(-24x+9*(2(10x+1))*3-36)
We calculate terms in parentheses: +(2(10x+1)), so:We get rid of parentheses
2(10x+1)
We multiply parentheses
20x+2
Back to the equation:
+(20x+2)
-10x+(-24x+9*(2(10x+1))*3-36)+20x-4*9)/(2(10x+1))*3+9)-16+8+2=0
We multiply all the terms by the denominator
-10x*(2(10x+1))*3+9)-16+8+2+((-24x+9*(2(10x+1))*3-36))*(2(10x+1))*3+9)-16+8+2+20x*(2(10x+1))*3+9)-16+8+2-4*9)=0
We add all the numbers together, and all the variables
-10x*(2(10x+1))*3+9)-16+8+2+((-24x+9*(2(10x+1))*3-36))*(2(10x+1))*3+9)-16+8+2+20x*(2(10x=0
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