2y-2=4(y+1)

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Solution for 2y-2=4(y+1) equation:



2y-2=4(y+1)
We move all terms to the left:
2y-2-(4(y+1))=0
We calculate terms in parentheses: -(4(y+1)), so:
4(y+1)
We multiply parentheses
4y+4
Back to the equation:
-(4y+4)
We get rid of parentheses
2y-4y-4-2=0
We add all the numbers together, and all the variables
-2y-6=0
We move all terms containing y to the left, all other terms to the right
-2y=6
y=6/-2
y=-3

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