8-4(3x-2)=6-(5x+4)

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Solution for 8-4(3x-2)=6-(5x+4) equation: 



8-4(3x-2)=6-(5x+4)

We move all terms to the left:

8-4(3x-2)-(6-(5x+4))=0

We multiply parentheses

-12x-(6-(5x+4))+8+8=0



We calculate terms in parentheses: -(6-(5x+4)), so:

6-(5x+4)

determiningTheFunctionDomain
-(5x+4)+6

We get rid of parentheses

-5x-4+6

We add all the numbers together, and all the variables

-5x+2

Back to the equation:

-(-5x+2)



We add all the numbers together, and all the variables

-12x-(-5x+2)+16=0

We get rid of parentheses

-12x+5x-2+16=0

We add all the numbers together, and all the variables

-7x+14=0

We move all terms containing x to the left, all other terms to the right

-7x=-14

x=-14/-7

x=+2

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