(-9+6i)(3-2i)=0

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Solution for (-9+6i)(3-2i)=0 equation: 



(-9+6i)(3-2i)=0

We add all the numbers together, and all the variables

(6i-9)(-2i+3)=0

We multiply parentheses ..

(-12i^2+18i+18i-27)=0

We get rid of parentheses

-12i^2+18i+18i-27=0

We add all the numbers together, and all the variables

-12i^2+36i-27=0

a = -12; b = 36; c = -27;
Δ = b2-4ac
Δ = 362-4·(-12)·(-27)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$i=\frac{-b}{2a}=\frac{-36}{-24}=1+1/2$

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