8-3y=2(4y+7)/5

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Solution for 8-3y=2(4y+7)/5 equation: 



8-3y=2(4y+7)/5

We move all terms to the left:

8-3y-(2(4y+7)/5)=0

We multiply all the terms by the denominator


-3y*5)-(2(4y+7)+8*5)=0

We add all the numbers together, and all the variables

-3y*5)-(2(4y+7)=0

Wy multiply elements

-15y^2=0

a = -15; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-15)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{-30}=0$

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