180=(4x+10)+(12x-6)+(3x+5)

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Solution for 180=(4x+10)+(12x-6)+(3x+5) equation: 



180=(4x+10)+(12x-6)+(3x+5)

We move all terms to the left:

180-((4x+10)+(12x-6)+(3x+5))=0



We calculate terms in parentheses: -((4x+10)+(12x-6)+(3x+5)), so:

(4x+10)+(12x-6)+(3x+5)

We get rid of parentheses

4x+12x+3x+10-6+5

We add all the numbers together, and all the variables

19x+9

Back to the equation:

-(19x+9)



We get rid of parentheses

-19x-9+180=0

We add all the numbers together, and all the variables

-19x+171=0

We move all terms containing x to the left, all other terms to the right

-19x=-171

x=-171/-19

x=+9

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