8-2c=2(4-c)

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Solution for 8-2c=2(4-c) equation: 



8-2c=2(4-c)

We move all terms to the left:

8-2c-(2(4-c))=0

We add all the numbers together, and all the variables

-2c-(2(-1c+4))+8=0



We calculate terms in parentheses: -(2(-1c+4)), so:

2(-1c+4)

We multiply parentheses

-2c+8

Back to the equation:

-(-2c+8)



We get rid of parentheses

-2c+2c-8+8=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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