3x(x-3)=x-19

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Solution for 3x(x-3)=x-19 equation: 



3x(x-3)=x-19

We move all terms to the left:

3x(x-3)-(x-19)=0

We multiply parentheses

3x^2-9x-(x-19)=0

We get rid of parentheses

3x^2-9x-x+19=0

We add all the numbers together, and all the variables

3x^2-10x+19=0

a = 3; b = -10; c = +19;
Δ = b2-4ac
Δ = -102-4·3·19
Δ = -128
Delta is less than zero, so there is no solution for the equation

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