8-(z+2)=-5(3z+12)

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Solution for 8-(z+2)=-5(3z+12) equation: 



8-(z+2)=-5(3z+12)

We move all terms to the left:

8-(z+2)-(-5(3z+12))=0

We get rid of parentheses

-z-(-5(3z+12))-2+8=0



We calculate terms in parentheses: -(-5(3z+12)), so:

-5(3z+12)

We multiply parentheses

-15z-60

Back to the equation:

-(-15z-60)



We add all the numbers together, and all the variables

-1z-(-15z-60)+6=0

We get rid of parentheses

-1z+15z+60+6=0

We add all the numbers together, and all the variables

14z+66=0

We move all terms containing z to the left, all other terms to the right

14z=-66

z=-66/14

z=-4+5/7

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