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2x+5-(4x-2)=10-(5x-23)
We move all terms to the left:
2x+5-(4x-2)-(10-(5x-23))=0
We get rid of parentheses
2x-4x-(10-(5x-23))+2+5=0
We calculate terms in parentheses: -(10-(5x-23)), so:We add all the numbers together, and all the variables
10-(5x-23)
determiningTheFunctionDomain -(5x-23)+10
We get rid of parentheses
-5x+23+10
We add all the numbers together, and all the variables
-5x+33
Back to the equation:
-(-5x+33)
-2x-(-5x+33)+7=0
We get rid of parentheses
-2x+5x-33+7=0
We add all the numbers together, and all the variables
3x-26=0
We move all terms containing x to the left, all other terms to the right
3x=26
x=26/3
x=8+2/3
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