8-(q-5)=2(3q-10)

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Solution for 8-(q-5)=2(3q-10) equation: 



8-(q-5)=2(3q-10)

We move all terms to the left:

8-(q-5)-(2(3q-10))=0

We get rid of parentheses

-q-(2(3q-10))+5+8=0



We calculate terms in parentheses: -(2(3q-10)), so:

2(3q-10)

We multiply parentheses

6q-20

Back to the equation:

-(6q-20)



We add all the numbers together, and all the variables

-1q-(6q-20)+13=0

We get rid of parentheses

-1q-6q+20+13=0

We add all the numbers together, and all the variables

-7q+33=0

We move all terms containing q to the left, all other terms to the right

-7q=-33

q=-33/-7

q=4+5/7

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