1/3(n+2)+2=1/6(6n-12)

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Solution for 1/3(n+2)+2=1/6(6n-12) equation: 



1/3(n+2)+2=1/6(6n-12)

We move all terms to the left:

1/3(n+2)+2-(1/6(6n-12))=0



Domain of the equation: 3(n+2)!=0

n∈R





Domain of the equation: 6(6n-12))!=0

n∈R



We calculate fractions


(6n6/(3(n+2)*6(6n-12)))+(-3nn/(3(n+2)*6(6n-12)))+2=0



We calculate terms in parentheses: +(6n6/(3(n+2)*6(6n-12))), so:

6n6/(3(n+2)*6(6n-12))

We multiply all the terms by the denominator


6n6

We add all the numbers together, and all the variables

6n^6

We do not support enpression: n^6

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