8-(n-6)=-4(3+n)+5

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Solution for 8-(n-6)=-4(3+n)+5 equation: 



8-(n-6)=-4(3+n)+5

We move all terms to the left:

8-(n-6)-(-4(3+n)+5)=0

We add all the numbers together, and all the variables

-(n-6)-(-4(n+3)+5)+8=0

We get rid of parentheses

-n-(-4(n+3)+5)+6+8=0



We calculate terms in parentheses: -(-4(n+3)+5), so:

-4(n+3)+5

We multiply parentheses

-4n-12+5

We add all the numbers together, and all the variables

-4n-7

Back to the equation:

-(-4n-7)



We add all the numbers together, and all the variables

-1n-(-4n-7)+14=0

We get rid of parentheses

-1n+4n+7+14=0

We add all the numbers together, and all the variables

3n+21=0

We move all terms containing n to the left, all other terms to the right

3n=-21

n=-21/3

n=-7

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