7(7+4a)=7(1+6a)

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Solution for 7(7+4a)=7(1+6a) equation: 



7(7+4a)=7(1+6a)

We move all terms to the left:

7(7+4a)-(7(1+6a))=0

We add all the numbers together, and all the variables

7(4a+7)-(7(6a+1))=0

We multiply parentheses

28a-(7(6a+1))+49=0



We calculate terms in parentheses: -(7(6a+1)), so:

7(6a+1)

We multiply parentheses

42a+7

Back to the equation:

-(42a+7)



We get rid of parentheses

28a-42a-7+49=0

We add all the numbers together, and all the variables

-14a+42=0

We move all terms containing a to the left, all other terms to the right

-14a=-42

a=-42/-14

a=+3

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