8-(n-4)=3(n+3)

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Solution for 8-(n-4)=3(n+3) equation: 



8-(n-4)=3(n+3)

We move all terms to the left:

8-(n-4)-(3(n+3))=0

We get rid of parentheses

-n-(3(n+3))+4+8=0



We calculate terms in parentheses: -(3(n+3)), so:

3(n+3)

We multiply parentheses

3n+9

Back to the equation:

-(3n+9)



We add all the numbers together, and all the variables

-1n-(3n+9)+12=0

We get rid of parentheses

-1n-3n-9+12=0

We add all the numbers together, and all the variables

-4n+3=0

We move all terms containing n to the left, all other terms to the right

-4n=-3

n=-3/-4

n=3/4

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