(3m+2)(m=3)-(2m-1)(m+3)=0

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Solution for (3m+2)(m=3)-(2m-1)(m+3)=0 equation: 



(3m+2)(m=3)-(2m-1)(m+3)=0

We move all terms to the left:

(3m+2)(m-(3)-(2m-1)(m+3))=0

We multiply parentheses ..

(3m+2)(m-3-(+2m^2+6m-1m-3))=0



We calculate terms in parentheses: +(3m+2)(m-3-(+2m^2+6m-1m-3)), so:

3m+2)(m-3-(+2m^2+6m-1m-3)

determiningTheFunctionDomain
-(+2m^2+6m-1m-3)+3m+2)(m-3

We get rid of parentheses

-2m^2-6m+1m+3m+2)(m+3-3

We add all the numbers together, and all the variables

-2m^2-2m+2)(m

Back to the equation:

+(-2m^2-2m+2)(m)



We multiply parentheses

-2m^3-2m^2+2m=0

We do not support empression: m^3

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