8-(3x-8)=12+4(8x+12)

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Solution for 8-(3x-8)=12+4(8x+12) equation: 



8-(3x-8)=12+4(8x+12)

We move all terms to the left:

8-(3x-8)-(12+4(8x+12))=0

We get rid of parentheses

-3x-(12+4(8x+12))+8+8=0



We calculate terms in parentheses: -(12+4(8x+12)), so:

12+4(8x+12)

determiningTheFunctionDomain
4(8x+12)+12

We multiply parentheses

32x+48+12

We add all the numbers together, and all the variables

32x+60

Back to the equation:

-(32x+60)



We add all the numbers together, and all the variables

-3x-(32x+60)+16=0

We get rid of parentheses

-3x-32x-60+16=0

We add all the numbers together, and all the variables

-35x-44=0

We move all terms containing x to the left, all other terms to the right

-35x=44

x=44/-35

x=-1+9/35

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