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1-2x=x+4-6x/x=3
We move all terms to the left:
1-2x-(x+4-6x/x)=0
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-2x-(x-6x/x+4)+1=0
We get rid of parentheses
-2x-x+6x/x-4+1=0
We multiply all the terms by the denominator
-2x*x-x*x+6x-4*x+1*x=0
We add all the numbers together, and all the variables
3x-2x*x-x*x=0
Wy multiply elements
-2x^2-1x^2+3x=0
We add all the numbers together, and all the variables
-3x^2+3x=0
a = -3; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·(-3)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*-3}=\frac{-6}{-6} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*-3}=\frac{0}{-6} =0 $
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