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8-(2x-9)=5+(x-4)
We move all terms to the left:
8-(2x-9)-(5+(x-4))=0
We get rid of parentheses
-2x-(5+(x-4))+9+8=0
We calculate terms in parentheses: -(5+(x-4)), so:We add all the numbers together, and all the variables
5+(x-4)
determiningTheFunctionDomain (x-4)+5
We get rid of parentheses
x-4+5
We add all the numbers together, and all the variables
x+1
Back to the equation:
-(x+1)
-2x-(x+1)+17=0
We get rid of parentheses
-2x-x-1+17=0
We add all the numbers together, and all the variables
-3x+16=0
We move all terms containing x to the left, all other terms to the right
-3x=-16
x=-16/-3
x=5+1/3
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