2(y+1)=3(y+2)

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Solution for 2(y+1)=3(y+2) equation: 



2(y+1)=3(y+2)

We move all terms to the left:

2(y+1)-(3(y+2))=0

We multiply parentheses

2y-(3(y+2))+2=0



We calculate terms in parentheses: -(3(y+2)), so:

3(y+2)

We multiply parentheses

3y+6

Back to the equation:

-(3y+6)



We get rid of parentheses

2y-3y-6+2=0

We add all the numbers together, and all the variables

-1y-4=0

We move all terms containing y to the left, all other terms to the right

-y=4

y=4/-1

y=-4

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