8-(2q-6)+5q=2(3q-1)+10

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Solution for 8-(2q-6)+5q=2(3q-1)+10 equation: 



8-(2q-6)+5q=2(3q-1)+10

We move all terms to the left:

8-(2q-6)+5q-(2(3q-1)+10)=0

We add all the numbers together, and all the variables

5q-(2q-6)-(2(3q-1)+10)+8=0

We get rid of parentheses

5q-2q-(2(3q-1)+10)+6+8=0



We calculate terms in parentheses: -(2(3q-1)+10), so:

2(3q-1)+10

We multiply parentheses

6q-2+10

We add all the numbers together, and all the variables

6q+8

Back to the equation:

-(6q+8)



We add all the numbers together, and all the variables

3q-(6q+8)+14=0

We get rid of parentheses

3q-6q-8+14=0

We add all the numbers together, and all the variables

-3q+6=0

We move all terms containing q to the left, all other terms to the right

-3q=-6

q=-6/-3

q=+2

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