3(w-2)+5(2-w)=16

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Solution for 3(w-2)+5(2-w)=16 equation: 



3(w-2)+5(2-w)=16

We move all terms to the left:

3(w-2)+5(2-w)-(16)=0

We add all the numbers together, and all the variables

3(w-2)+5(-1w+2)-16=0

We multiply parentheses

3w-5w-6+10-16=0

We add all the numbers together, and all the variables

-2w-12=0

We move all terms containing w to the left, all other terms to the right

-2w=12

w=12/-2

w=-6

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