29=13+2(5g-2)

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Solution for 29=13+2(5g-2) equation: 



29=13+2(5g-2)

We move all terms to the left:

29-(13+2(5g-2))=0



We calculate terms in parentheses: -(13+2(5g-2)), so:

13+2(5g-2)

determiningTheFunctionDomain
2(5g-2)+13

We multiply parentheses

10g-4+13

We add all the numbers together, and all the variables

10g+9

Back to the equation:

-(10g+9)



We get rid of parentheses

-10g-9+29=0

We add all the numbers together, and all the variables

-10g+20=0

We move all terms containing g to the left, all other terms to the right

-10g=-20

g=-20/-10

g=+2

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