8-(2c+3)=4(c+6)+c

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Solution for 8-(2c+3)=4(c+6)+c equation: 



8-(2c+3)=4(c+6)+c

We move all terms to the left:

8-(2c+3)-(4(c+6)+c)=0

We get rid of parentheses

-2c-(4(c+6)+c)-3+8=0



We calculate terms in parentheses: -(4(c+6)+c), so:

4(c+6)+c

We add all the numbers together, and all the variables

c+4(c+6)

We multiply parentheses

c+4c+24

We add all the numbers together, and all the variables

5c+24

Back to the equation:

-(5c+24)



We add all the numbers together, and all the variables

-2c-(5c+24)+5=0

We get rid of parentheses

-2c-5c-24+5=0

We add all the numbers together, and all the variables

-7c-19=0

We move all terms containing c to the left, all other terms to the right

-7c=19

c=19/-7

c=-2+5/7

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