27-(2c+40)=2(c+4)+c

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Solution for 27-(2c+40)=2(c+4)+c equation: 



27-(2c+40)=2(c+4)+c

We move all terms to the left:

27-(2c+40)-(2(c+4)+c)=0

We get rid of parentheses

-2c-(2(c+4)+c)-40+27=0



We calculate terms in parentheses: -(2(c+4)+c), so:

2(c+4)+c

We add all the numbers together, and all the variables

c+2(c+4)

We multiply parentheses

c+2c+8

We add all the numbers together, and all the variables

3c+8

Back to the equation:

-(3c+8)



We add all the numbers together, and all the variables

-2c-(3c+8)-13=0

We get rid of parentheses

-2c-3c-8-13=0

We add all the numbers together, and all the variables

-5c-21=0

We move all terms containing c to the left, all other terms to the right

-5c=21

c=21/-5

c=-4+1/5

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