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8+8(5x-4)=-8-5(8x+9)
We move all terms to the left:
8+8(5x-4)-(-8-5(8x+9))=0
We multiply parentheses
40x-(-8-5(8x+9))-32+8=0
We calculate terms in parentheses: -(-8-5(8x+9)), so:We add all the numbers together, and all the variables
-8-5(8x+9)
determiningTheFunctionDomain -5(8x+9)-8
We multiply parentheses
-40x-45-8
We add all the numbers together, and all the variables
-40x-53
Back to the equation:
-(-40x-53)
40x-(-40x-53)-24=0
We get rid of parentheses
40x+40x+53-24=0
We add all the numbers together, and all the variables
80x+29=0
We move all terms containing x to the left, all other terms to the right
80x=-29
x=-29/80
x=-29/80
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