20/4x-4=5/x

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Solution for 20/4x-4=5/x equation: 



20/4x-4=5/x

We move all terms to the left:

20/4x-4-(5/x)=0



Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R





Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

20/4x-(+5/x)-4=0

We get rid of parentheses

20/4x-5/x-4=0

We calculate fractions


20x/4x^2+(-20x)/4x^2-4=0

We multiply all the terms by the denominator


20x+(-20x)-4*4x^2=0

Wy multiply elements

-16x^2+20x+(-20x)=0

We get rid of parentheses

-16x^2+20x-20x=0

We add all the numbers together, and all the variables

-16x^2=0

a = -16; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-16)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-32}=0$

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