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8+4(x-2)-5(x-3)=2(5-2x)
We move all terms to the left:
8+4(x-2)-5(x-3)-(2(5-2x))=0
We add all the numbers together, and all the variables
4(x-2)-5(x-3)-(2(-2x+5))+8=0
We multiply parentheses
4x-5x-(2(-2x+5))-8+15+8=0
We calculate terms in parentheses: -(2(-2x+5)), so:We add all the numbers together, and all the variables
2(-2x+5)
We multiply parentheses
-4x+10
Back to the equation:
-(-4x+10)
-1x-(-4x+10)+15=0
We get rid of parentheses
-1x+4x-10+15=0
We add all the numbers together, and all the variables
3x+5=0
We move all terms containing x to the left, all other terms to the right
3x=-5
x=-5/3
x=-1+2/3
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