11-3(r-7)=16-(r+2)

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Solution for 11-3(r-7)=16-(r+2) equation: 



11-3(r-7)=16-(r+2)

We move all terms to the left:

11-3(r-7)-(16-(r+2))=0

We multiply parentheses

-3r-(16-(r+2))+21+11=0



We calculate terms in parentheses: -(16-(r+2)), so:

16-(r+2)

determiningTheFunctionDomain
-(r+2)+16

We get rid of parentheses

-r-2+16

We add all the numbers together, and all the variables

-1r+14

Back to the equation:

-(-1r+14)



We add all the numbers together, and all the variables

-3r-(-1r+14)+32=0

We get rid of parentheses

-3r+1r-14+32=0

We add all the numbers together, and all the variables

-2r+18=0

We move all terms containing r to the left, all other terms to the right

-2r=-18

r=-18/-2

r=+9

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