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8+2x-4=2(x+2)
We move all terms to the left:
8+2x-4-(2(x+2))=0
We add all the numbers together, and all the variables
2x-(2(x+2))+4=0
We calculate terms in parentheses: -(2(x+2)), so:We get rid of parentheses
2(x+2)
We multiply parentheses
2x+4
Back to the equation:
-(2x+4)
2x-2x-4+4=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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