4(r+20)=1/5(20r-400)

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Solution for 4(r+20)=1/5(20r-400) equation: 



4(r+20)=1/5(20r-400)

We move all terms to the left:

4(r+20)-(1/5(20r-400))=0



Domain of the equation: 5(20r-400))!=0

r∈R



We multiply parentheses

4r-(1/5(20r-400))+80=0

We multiply all the terms by the denominator


4r*5(20r-400))-(1+80*5(20r-400))=0

Wy multiply elements

20r^2(2+400r(2=0

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