8+2(5m-8)+3(m+2)=12+4(2m-1)

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Solution for 8+2(5m-8)+3(m+2)=12+4(2m-1) equation: 



8+2(5m-8)+3(m+2)=12+4(2m-1)

We move all terms to the left:

8+2(5m-8)+3(m+2)-(12+4(2m-1))=0

We multiply parentheses

10m+3m-(12+4(2m-1))-16+6+8=0



We calculate terms in parentheses: -(12+4(2m-1)), so:

12+4(2m-1)

determiningTheFunctionDomain
4(2m-1)+12

We multiply parentheses

8m-4+12

We add all the numbers together, and all the variables

8m+8

Back to the equation:

-(8m+8)



We add all the numbers together, and all the variables

13m-(8m+8)-2=0

We get rid of parentheses

13m-8m-8-2=0

We add all the numbers together, and all the variables

5m-10=0

We move all terms containing m to the left, all other terms to the right

5m=10

m=10/5

m=2

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