(7x+19)+(15x-1)=(12x+3)+(4x-3)

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Solution for (7x+19)+(15x-1)=(12x+3)+(4x-3) equation: 



(7x+19)+(15x-1)=(12x+3)+(4x-3)

We move all terms to the left:

(7x+19)+(15x-1)-((12x+3)+(4x-3))=0

We get rid of parentheses

7x+15x-((12x+3)+(4x-3))+19-1=0



We calculate terms in parentheses: -((12x+3)+(4x-3)), so:

(12x+3)+(4x-3)

We get rid of parentheses

12x+4x+3-3

We add all the numbers together, and all the variables

16x

Back to the equation:

-(16x)



We add all the numbers together, and all the variables

6x+18=0

We move all terms containing x to the left, all other terms to the right

6x=-18

x=-18/6

x=-3

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