-6(x-2)-(x+3)=(2x-8)-9

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Solution for -6(x-2)-(x+3)=(2x-8)-9 equation: 



-6(x-2)-(x+3)=(2x-8)-9

We move all terms to the left:

-6(x-2)-(x+3)-((2x-8)-9)=0

We multiply parentheses

-6x-(x+3)-((2x-8)-9)+12=0

We get rid of parentheses

-6x-x-((2x-8)-9)-3+12=0



We calculate terms in parentheses: -((2x-8)-9), so:

(2x-8)-9

We get rid of parentheses

2x-8-9

We add all the numbers together, and all the variables

2x-17

Back to the equation:

-(2x-17)



We add all the numbers together, and all the variables

-7x-(2x-17)+9=0

We get rid of parentheses

-7x-2x+17+9=0

We add all the numbers together, and all the variables

-9x+26=0

We move all terms containing x to the left, all other terms to the right

-9x=-26

x=-26/-9

x=2+8/9

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