8+2(3x-5)=4-3(x+1)

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Solution for 8+2(3x-5)=4-3(x+1) equation: 



8+2(3x-5)=4-3(x+1)

We move all terms to the left:

8+2(3x-5)-(4-3(x+1))=0

We multiply parentheses

6x-(4-3(x+1))-10+8=0



We calculate terms in parentheses: -(4-3(x+1)), so:

4-3(x+1)

determiningTheFunctionDomain
-3(x+1)+4

We multiply parentheses

-3x-3+4

We add all the numbers together, and all the variables

-3x+1

Back to the equation:

-(-3x+1)



We add all the numbers together, and all the variables

6x-(-3x+1)-2=0

We get rid of parentheses

6x+3x-1-2=0

We add all the numbers together, and all the variables

9x-3=0

We move all terms containing x to the left, all other terms to the right

9x=3

x=3/9

x=1/3

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