(8x2)+(3x2)=11x

Solution for (8x2)+(3x2)=11x equation:

(8x^2)+(3x^2)=11x

We move all terms to the left:

(8x^2)+(3x^2)-(11x)=0

We add all the numbers together, and all the variables

11x^2-11x=0

a = 11; b = -11; c = 0;
Δ = b2-4ac
Δ = -112-4·11·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-11}{2*11}=\frac{0}{22}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+11}{2*11}=\frac{22}{22}
=1
$