8+(4/5x)=29+(1/5x)

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Solution for 8+(4/5x)=29+(1/5x) equation: 



8+(4/5x)=29+(1/5x)

We move all terms to the left:

8+(4/5x)-(29+(1/5x))=0



Domain of the equation: 5x)!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 5x))!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+4/5x)-(29+(+1/5x))+8=0

We get rid of parentheses

4/5x-(29+(+1/5x))+8=0

We calculate fractions


20x/25x^2+(-(29+(+1*5x)/25x^2+8=0

We calculate fractions

We do not support expression: x^4

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